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must BE str not int

age = 18s = 'age: {}'.format(age) # DO NOT code like `s='age: '+age`

去掉双引号

import randomname = input("Please enter your name:")name = name.strip()first_name, last_name = name.split()index = str(random.randint(0, 999))user_name = first_name[0].lower() + last_name[0:3].lower() + index.zfill(3)print('You...

应该是link创建了以后还没存,表中还没那个link,link.save()一下看看

Private Sub TextBox6_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles TextBox6.TextChanged Dim sdr As SqlDataReader Dim sql As String sql = "select 费率 from 收费标准信息表 where 车型='" + Me.Text...

Python allow to concatenate strings by '+', but here, your p is an integer. So, to solve it, you can use either of these: 1. print 'Is your secret number " + str(p) + "?" 2. print 'Is your secret number %d?"%p (for multiple int...

python 3.X input 输入默认是字符串 改为int (g)+65

你的类的声明与实现不一致导致的错误 声明部分:String(char*const ch); 实现部分:String::String(const char*const ch) 编译器会认为这是两个不同的函数,是另一次重载,所以编译不能通过。 可以改为: #include using namespace std; class S...

out_put是integer的子类型,取值范围是0~10。因此不能对其赋值"1111111",只能赋值0~10中的某一个数。 错误之处: if(check'event and check='1') then out_put

查找(find) 语法: size_type find( const basic_string &str, size_type index ); size_type find( const char *str, size_type index ); size_type find( const char *str, size_type index, size_type length ); size_type find( char ch, siz...

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