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ios 字符串

假设要查询的字符串味: NSString *searchStr = @"a string with substr"; 查询(是否)被包含的字符串为@"substr",则通过下面的判断: if ([searchStr rangeOfString:@"substr"].location != NSNotFound) { //条件为真,表示字符串searchStr包...

[原字符串 stringByReplacingOccurrencesOfString:@"目标字符串" withString:@"要替换的字符串"]

1, 创建一个NSString对象 简单方法: NSString *aString = @"我是个NS字符串!"; //除了引号外加@, 没别的区别不需要操心内存管理 NSString *aString = [[NSString alloc] initWithFormat:@"这也是个NS字符串!"];//要去retain和release这个字符...

/*! * @brief 把格式化的JSON格式的字符串转换成字典 * @param jsonString JSON格式的字符串 * @return 返回字典 */+ (NSDictionary *)dictionaryWithJsonString:(NSString *)jsonString { if (jsonString == nil) { return nil; } NSData *json...

+ (id)stringWithContentsOfFile:(NSString *)path usedEncoding:(NSStringEncoding *)enc error:(NSError **)error; 是自动判断encode,如果打开成功,把encode放在enc 里,返回给调用者。 声明一个NSStringEncoding 类型(其实就是NSUInteger...

下面的代码可能对你有帮助:CFUUIDRef identifier = CFUUIDCreate(NULL);NSString* identifierString = (NSString*)CFUUIDCreateString(NULL, identifier);CFRelease(identifier); 查看原帖>>

1、NSData 转NSString NSString *result =[[ NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]; 2、字符串转Data NSString *str =@"jesfds"; NSData *data =[str dataUsingEncoding:NSUTF8StringEncoding];

[str length]

NSString *string = @"qwer"; NSMutableString *newString = [[NSMutableString alloc] initWithCapacity:string.length]; for (int i = string.length - 1; i >=0 ; i --) { unichar ch = [string characterAtIndex:i]; [newString appendForma...

你好,如果你把楼上的代码改成: NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"2014-01-20 14:36:07"]; NSString *strDate = [dateFormatter stringFromDate:[NSDate date]]; NSLog(@"%@"...

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